JEE MATHEMATICS MCQ: TRIGONOMETRY RATIOS

1 Easy

1 of 1

Application +4 | -1

\cos x+\cos ^2 x=1

, then the value of

\sin ^{12} x+

3 \sin ^{10} x+3 \sin ^8 x+\sin ^6 x-1

is equal to

View answer and explanation

Correct option: D

Option D (0) is correct because given

\cos x + \cos^2 x = 1

, we can deduce

\cos x = \sin^2 x

. Substituting this into the expression and simplifying leads to 0.

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\tan \alpha=\frac{p}{q}

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\alpha

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\triangle A B C

C

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\sin ^2 \frac{A}{2}+\sin ^2 \frac{B}{2}+\sin ^2 \frac{C}{2}=

\sin ^2(A / 2)+\sin ^2(B / 2)-\sin ^2(C / 2)=