JEE MATHEMATICS MCQ: TRIGONOMETRY RATIOS

1 Easy

1 of 1

Understanding +4 | -1

The value of

\cos \,\,1^\circ \,\,\cos \,\,2^\circ \,\,\cos \,\,3^\circ \ldots \cos \,\,179^\circ

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Correct option: B

\mathrm{0}

Option B (0) is correct because the product includes cos(90°), which is 0, making the entire product zero.

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\tan \alpha=\frac{p}{q}

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\triangle A B C

C

{\sin ^6}\,\,\theta + {\cos ^6}\,\,\theta + 3{\sin ^2}\,\,\theta \,\,{\cos ^2}\,\,\theta

\sin ^2 \frac{A}{2}+\sin ^2 \frac{B}{2}+\sin ^2 \frac{C}{2}=

\sin ^2(A / 2)+\sin ^2(B / 2)-\sin ^2(C / 2)=