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NEET UG CHEMISTRY MCQ: REDOX REACTIONS

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Which combination is odd with respect to oxidation numbers of S,Cr,N\mathrm{S},\mathrm{Cr},\mathrm{N} and H\mathrm{H} respectively:
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Correct option: C
NH3,NH4+,N3H,NO2−\mathrm{N}{\mathrm{H}_3},\mathrm{NH}_4^ + ,{\mathrm{N}_3}\mathrm{H},\mathrm{NO}_2^ -
Option C (NH3,NH4+,N3H,NO2−\mathrm{N}{\mathrm{H}_3},\mathrm{NH}_4^ + ,{\mathrm{N}_3}\mathrm{H},\mathrm{NO}_2^ -) is the odd combination because the oxidation state of H is +1 in the first three compounds, but it is not present in the last compound.

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The oxidation state of iron in sodium nitroprusside is : Titrations in which liberated I2{I_2} is estimated to carry out the volumetric estimations are known as ….titrations. It is found that V forms a double salt isomorphous with Mohr’s salt. The oxidation number of V in this compound is : For redox reaction, MnO4−+C2O42−+H+→Mn2++CO2+H2O\mathrm{MnO}_4^ - + {\mathrm{C}_2}\mathrm{O}_4^{2 - } + {\mathrm{H}^ + } \to \mathrm{M}{\mathrm{n}^{2 + }} + \mathrm{C}{\mathrm{O}_2} + {\mathrm{H}_2}\mathrm{O} coefficient of reactants in balanced states are MnO4−\mathrm{MnO}_4^ -, C2O42−{\mathrm{C}_2}\mathrm{O}_4^{2 - }, H+{\mathrm{H}^ + } Which one of the following reaction is possible at anode? The couple having oxidised and reduced forms of a substance taking part in an oxidation or reduction half-reaction is called
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