The hydrogen ion concentration of a ${10^{ - 8}}M\;{\rm{HCl}}$ aqueous solution at $298\;{\rm{K}}\;\left( {{K_w} = {{10}^{ - 14}}} \right)$ is:

NEET UG CHEMISTRY MCQ: Equilibrium

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Application +4 | -1

The hydrogen ion concentration of a

{10^{ - 8}}M\;\mathrm{HCl}

aqueous solution at

298\;\mathrm{K}\;\left( {{K_w} = {{10}^{ - 14}}} \right)

is:

View answer and explanation

Correct option: D

1.0525 \times {10^{ - 7}}\;M

Option D (

1.0525 \times {10^{ - 7}}\;M

) is correct because it accounts for both the HCl contribution and the autoionization of water.

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Mg{(HC{O_3})_2}

MgC{O_3}

Mg{(OH)_2}

MgC{O_3}

K_{\mathrm{P}}

\mathrm{CaCO}_3

4.5 \times 10^{-2}

\mathrm{C}(\mathrm{s})+\mathrm{CO}_2(\mathrm{g}) \rightleftharpoons 2 \mathrm{CO}(\mathrm{g}),

K_{\mathrm{P}}

2.0 \mathrm{~atm}.

\mathrm{CaO}

\mathrm{CaCO}_3

+

\leftrightharpoons

\mathrm{PC}{\mathrm{l}_5}\leftrightharpoons\mathrm{PC}{\mathrm{l}_3} + \mathrm{C}{\mathrm{l}_2}

{K_{\mathrm{eq}}} = 0.41

\mathrm{p}{K_a}