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JEE MATHEMATICS MCQ: INDEFINITE INTEGRATION

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Analyzing +4 | -1
Let ff be a non-negative function defined on the interval [0,1]\left[ {0,1} \right]. If ∫0x  1  −  ( f′(t))2  dt=∫0x  f  (t)  dt,  0≤  x  ≤1\int \nolimits_0^x \,\,\sqrt {1\,\, - \,\,{{\left( {\,f'\left( t \right)} \right)}^2}} \,\,dt = \int \nolimits_0^x \,\,f\,\,\left( t \right)\,\,dt,\,\,0 \le \,\,x\,\, \le 1 and f  (0)=0f\,\,\left( 0 \right) = 0, then

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Correct option: C
f  (12)  <  12f\,\,\left( {\frac{1}{2}} \right)\,\, < \,\,\frac{1}{2} and f  (13)  <  13f\,\,\left( {\frac{1}{3}} \right)\,\, < \,\,\frac{1}{3}
Option C (f  (12)  <  12f\,\,\left( {\frac{1}{2}} \right)\,\,< \,\,\frac{1}{2} and f  (13)  <  13f\,\,\left( {\frac{1}{3}} \right)\,\,< \,\,\frac{1}{3}) is correct because f(x)=sin⁡(x)f(x) = \sin(x) and sin⁡(x)<x\sin(x) < x for all positive x.

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