JEE MATHEMATICS MCQ: TANGENTS & NORMALS

1 Hard

1 of 1

Application +4 | -1

For the curve

\mathrm{y}=3 \sin \theta \cos \theta, \mathrm{x}=\mathrm{e}^\theta \sin \theta

0 \leq \theta \leq \pi

, the tangent is parallel to

x

-axis when

\theta

is:

View answer and explanation

Correct option: C

\frac{\pi}{4}

Option C (

\frac{{\pi}}{{4}}

) is correct because the tangent is parallel to the x-axis when

\frac{{dy}}{{dx}} = 0

, which occurs when

\theta = \frac{{\pi}}{{4}}

after differentiating and simplifying.

More Questions from TANGENTS & NORMALS

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a

y=x^3-a x

x^2 y=1-y

x y=1-y

C

y^3-3 x y+2=0

H

\mathrm{C}

x

V

C

y

y-e^{x y}+x=0

y = f\left( x \right)

x

x = a\left( {\theta - \sin \theta } \right),\;y = a\left( {1 + \cos \theta } \right)

\theta = \left( {2k + 1} \right)\pi ,\;k \in Z