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JEE MATHEMATICS MCQ: FUNCTIONS

1 Easy

1 of 1

Application +4 | -1

Given

f\left( x \right) = \log \left( {\frac{{1 + x}}{{1 - x}}} \right)\;and\;g\left( x \right) = \frac{{3\;x + {x^3}}}{{1 + 3\;{x^2}}},

then

fog\left( x \right)

equals

View answer and explanation

Correct option: B

3\;f\left( x \right)

Option B (

3f(x)

) is correct because the composition of the functions simplifies to

3 \log \left( {\frac{{1 + x}}{{1 - x}}} \right)

.

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