NEET UG CHEMISTRY MCQ: Equilibrium

1 Hard

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Understanding +4 | -1

For the reactions

\mathrm{I}_2(\mathrm{aq}) \rightleftharpoons \mathrm{I}_2

(oil) Equilibrium constant is

\mathrm{K}_1

\mathrm{I}_2

(oil)

\rightleftharpoons \mathrm{I}_2

(ether) Equilibrium constant is

\mathrm{K}_2

for the reaction

\mathrm{I}_2(\mathrm{aq}) \rightleftharpoons \mathrm{I}_2

(ether) Equilibrium constant is

\mathrm{K}_3

The relation between

\mathrm{K}_1, \mathrm{K}_2, \mathrm{K}_3

View answer and explanation

Correct option: B

\mathrm{K}_3=\mathrm{K}_1 \mathrm{~K}_2

Option B is correct because the overall equilibrium constant K3 is the product of the individual equilibrium constants K1 and K2.

More Questions from Equilibrium

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Mg{(HC{O_3})_2}

MgC{O_3}

Mg{(OH)_2}

MgC{O_3}

K_{\mathrm{P}}

\mathrm{CaCO}_3

4.5 \times 10^{-2}

\mathrm{C}(\mathrm{s})+\mathrm{CO}_2(\mathrm{g}) \rightleftharpoons 2 \mathrm{CO}(\mathrm{g}),

K_{\mathrm{P}}

2.0 \mathrm{~atm}.

\mathrm{CaO}

\mathrm{CaCO}_3

+

\leftrightharpoons

\mathrm{PC}{\mathrm{l}_5}\leftrightharpoons\mathrm{PC}{\mathrm{l}_3} + \mathrm{C}{\mathrm{l}_2}

{K_{\mathrm{eq}}} = 0.41

\mathrm{p}{K_a}