JEE MATHEMATICS MCQ: COMPLEX NUMBERS

1 Easy

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Application +4 | -1

z=\cos \theta+i \sin \theta

is a root of

x^n+p_1 x^{n-1}+p_2 x^{n-2}+\ldots+p_n=0,

where

p_1, p_2, \ldots, p_n \in \mathbf{R}

,then the value of

7\left(p_1 \sin \theta+p_2 \sin 2 \theta+\ldots+p_n \sin (n \theta)\right)

View answer and explanation

Correct option: D

Option D (0) is correct because since the coefficients are real, the complex conjugate is also a root, leading to the given expression equaling 0.

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