JEE MATHEMATICS MCQ: INDEFINITE INTEGRATION

1 Easy

1 of 1

Application +4 | -1

\int(\sin 2 x-\cos 2 x) \mathrm{d} x=\frac{1}{\sqrt{2}} \sin (2 x+k)+C

then

View answer and explanation

Correct option: B

k=5 \pi / 4

Option B is correct because after integrating by parts and simplifying, the integral evaluates to

(x-1) \log (1-\sqrt{x})-\frac{1}{2} x-\sqrt{x}+C

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