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JEE MATHEMATICS MCQ: COMPLEX NUMBERS

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The value of the expression 1(2−ω)(2−ω2)+2(3−ω)(3−ω2)+….+(n−1)1(2-\omega)\left(2-\omega^2\right)+2(3-\omega)\left(3-\omega^2\right)+\ldots .+(n-1) (n−ω)(n−ω2)(n-\omega)\left(n-\omega^2\right), where ω\omega is an imaginary cube root of unity, is
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Correct option: B
(n(n+1)2)2−n\left(\frac{n(n+1)}{2}\right)^2-n
Option B ((n(n+1)2)2−n\left(\frac{{n(n+1)}}{{2}}\right)^2-n) is correct because the given expression can be simplified to a sum of cubes minus a linear term, which results in the given expression.

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