JEE PHYSICS MCQ: THERMODYNAMICS

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The coefficient of performance of a refrigerator work between

{10^ \circ }C

and

{20^ \circ }C

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Correct option: A

28.3

Option A (28.3) is correct because the coefficient of performance is calculated using the formula COP = T2/(T1-T2) where T1 and T2 are the absolute temperatures of the hot and cold reservoirs, respectively.

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The work done in which of the following process is zero? Water is used to cool the radiators of engines in cars because A gas expand

0.25\,\,{m^3}

at constant pressure

{10^3}N/{m^2},

the work done is A thermodynamic process in which temperature

T

of the system remains constant though other variable

P

and

V

may change, is called What is the slope for an isothermal process? For adiabatic processes

\left( {\gamma = \frac{{{C_p}}}{{{C_v}}}} \right)