JEE MATHEMATICS MCQ: INDEFINITE INTEGRATION

1 Easy

1 of 1

Analyzing +4 | -1

Let

f(x)=\left\{\sin \left(\tan ^{-1} x\right)+\sin \left(\cot ^{-1} x\right)\right\}^2-1

, where

|x|>1

and

\frac{d y}{d x}=\frac{1}{2} \frac{d}{d x}\left(\sin ^{-1} f(x)\right)

. If

y(\sqrt{3})=\frac{\pi}{3}

, then

y(-\sqrt{3})=

View answer and explanation

Correct option: B

-\frac{\pi}{3}

Option B (-

\frac{\pi}{3}

) is correct because after simplifying f(x) and using the given condition, we find y(-

\sqrt{3}

) = -

\frac{\pi}{3}

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