Skip to main content
Back to COMPLEX NUMBERS

JEE MATHEMATICS MCQ: COMPLEX NUMBERS

1 Hard
1 of 1
Analyzing +4 | -1
The common roots of the equations x3+2x2+2x+1=0{x^3} + 2{x^2} + 2x + 1 = 0 and 1+x2002+x2003=01 + {x^{2002}} + {x^{2003}} = 0 (where ω\omega is a complex cube root of unity)
View answer and explanation
Correct option: A
ω,ω2\omega ,{\omega ^2}
Option A (ω,ω2\omega, \omega^2) is correct because these are the common roots of both equations, where ω\omega is a complex cube root of unity.

More Questions from COMPLEX NUMBERS

Practice All Chapter MCQs →
Type at least 2 characters or jump directly:
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.