JEE MATHEMATICS MCQ: INDEFINITE INTEGRATION

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Application +4 | -1

\frac{d}{{dx}}\,\,\{ f\left( x \right) = \frac{1}{{1 + {x^2}}}

, then

\frac{d}{{dx}}\,\,\left\{ {f\left( {{x^3}} \right)} \right\}

View answer and explanation

Correct option: B

\frac{{3{x^2}}}{{1\,\, + \,\,{x^6}}}

Option B (

\frac{{3{x^2}}}{{1\\,\\ + \\,{x^6}}}

) is correct because it is the result of applying the chain rule after recognizing that

f(x) = \tan^{-1}(x)

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