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JEE PHYSICS MCQ: SYSTEM OF PARTICLES

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The instantaneous angular position of a point on a rotation wheel is given by the equation θ(t)=2t3−6t2\theta (t) = 2{t^3} - 6{t^2}. The torque on the wheel becomes zero at
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Correct option: B
t=1 sec⁡t = 1\,\sec
Option B (t=1 sec⁡t = 1\,\sec) is correct because the torque is zero when the angular acceleration is zero.

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