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JEE PHYSICS MCQ: DUAL NATURE OF RADIATION AND MATTER

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Analyzing +4 | -1
While doing his experiment, Millikan one day observed the following charges on a single drop
(i)6.563×10−19C6.563 \times {10^{ - 19}}C (ii) 8.204×10−19C8.204 \times {10^{ - 19}}C
(iii)11.50  ×10−19C  11.50\; \times {10^{ - 19}}C\; (iv)13.13×10−19C13.13 \times {10^{ - 19}}C
(v)16.48×10−19C    16.48 \times {10^{ - 19}}C\;\; (vi)18.09×10−19C18.09 \times {10^{ - 19}}C
From this data the value of the elementary charge (e)\left( e \right) was found to be
View answer and explanation
Correct option: A
1.641×10−19C1.641 \times {10^{ - 19}}C
Option A (1.641×10−19C1.641 \times {10^{ - 19}}C) is correct because it is the elementary charge calculated from the given Millikan's oil drop experiment data.

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