JEE MATHEMATICS MCQ: TRIGONOMETRY RATIOS

1 Easy

1 of 1

Application +4 | -1

\sin \,\,x + {\sin ^2}\,\,x = 1

, then the value of

{\cos ^{12}}\,\,x + 3\,\,{\cos ^{10}}\,\,x + 3\,\,{\cos ^8}\,\,x + {\cos ^6}\,\,x - 1

is equal to

View answer and explanation

Correct option: C

\mathrm{0}

Option C (0) is correct because by substituting

\sin x = \cos^2 x

and simplifying, the expression reduces to 1 - 1 = 0.

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C

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