JEE MATHEMATICS MCQ: INDEFINITE INTEGRATION

1 Easy

1 of 1

Application +4 | -1

\int e^{\tan ^{-1} x}\left(\frac{1+x+x^2}{1+x^2}\right) d x

is equal to

View answer and explanation

Correct option: A

x e^{\tan ^{-1} x}+c

Option A (

x e^{\tan ^{-1} x}+c

) is correct because recognizing the form

\int e^x (f(x) + f'(x)) dx = e^x f(x) + c

allows for direct integration after substitution.

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