JEE PHYSICS MCQ: THERMAL PROPERTIES OF MATTER

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A gas at

{27^0}C

and pressure of 30 atm is allowed to expand to atmosphere pressure and volume 15 times larger. The final temperature of the gas is?

View answer and explanation

Correct option: A

- {123^0}C

Option A (

- {123^0}C

) is correct because it is the final temperature calculated using the combined gas law, considering the changes in pressure and volume.

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n = \frac{{PV}}{{RT}},n =

{25^0}

{0^0}C

E\,\,W{m^{ - 2}}

\left( {\frac{T}{2}} \right)K