Question

A straight chain hydrocarbon has the molecular formula ${{\rm{C}}_8}{{\rm{H}}_{10}}$ . The hybridization for the carbon atoms from one end of the chain to the other are respectively $s{p^3},\;s{p^2},\;s{p^2},\;s{p^3},\;s{p^2},\;s{p^2},\;sp\;{\kern 1pt} {\kern 1pt} {\kern 1pt} {\kern 1pt} {\rm{and}}{\kern 1pt} {\kern 1pt} {\kern 1pt} \;sp$. The structural formula of the hydrocarbon would be :

Accepted Answer

${\rm{C}}{{\rm{H}}_3} - {\rm{CH}} = {\rm{CH}} - {\rm{C}}{{\rm{H}}_2} - {\rm{CH}} = {\rm{CH}} - {\rm{C\;}} \equiv {\rm{CH}}$

Answer

${\rm{C}}{{\rm{H}}_3} - {\rm{C}} \equiv {\rm{C}} - {\rm{C}}{{\rm{H}}_2} - {\rm{CH}} = {\rm{CH}} - {\rm{CH}} = {\rm{C}}{{\rm{H}}_2}$

Answer

${\rm{C}}{{\rm{H}}_3} - {\rm{C}}{{\rm{H}}_2} - {\rm{CH}} = {\rm{\;CH}} - {\rm{CH}} = {\rm{CH}} - {\rm{CH}} \equiv {\rm{CH}}$

Answer

${\rm{C}}{{\rm{H}}_3} - {\rm{CH}} = {\rm{CH}} - {\rm{C}}{{\rm{H}}_2} - {\rm{C}} \equiv {\rm{C}} - {\rm{CH}} = {\rm{C}}{{\rm{H}}_2}$

NEET UG CHEMISTRY MCQ: ORGANIC CHEMISTRY-SOME BASIC PRINCIPLES AND TECHNIQUES

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