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JEE PHYSICS MCQ: WORK-ENERGY-POWER

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Force acting on a particle moving in a straight line varies with the velocity of the particle as F=KvF=\frac{K}{v}. Here KK is constant. The work done by this force in time tt is
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Correct option: C
Kt\mathrm{Kt}
Option C (Kt\mathrm{Kt}) is correct because the work done is directly proportional to time, as derived from the relationship between force, velocity, and time.

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