The oxidation number of $Fe$ in ${{\rm{K}}_4}{\rm{Fe}}{\left( {{\rm{CN}}} \right)_6}$ is :

NEET UG CHEMISTRY MCQ: REDOX REACTIONS

1 Medium

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Application +4 | -1

The oxidation number of

Fe

{\mathrm{K}_4}\mathrm{Fe}{\left( {\mathrm{CN}} \right)_6}

is :

View answer and explanation

Correct option: A

+ 2

Option A (+2) is correct because K has +1 and CN has -1, balancing the overall charge of the complex.

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{I_2}

\mathrm{MnO}_4^ - + {\mathrm{C}_2}\mathrm{O}_4^{2 - } + {\mathrm{H}^ + } \to \mathrm{M}{\mathrm{n}^{2 + }} + \mathrm{C}{\mathrm{O}_2} + {\mathrm{H}_2}\mathrm{O}

\mathrm{MnO}_4^ -

{\mathrm{C}_2}\mathrm{O}_4^{2 - }

{\mathrm{H}^ + }