JEE MATHEMATICS MCQ: COMPLEX NUMBERS

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Application +4 | -1

z \neq 0

be a complex number such that

\left|z-\frac{1}{z}\right|=2

, then the maximum value of

|z|

View answer and explanation

Correct option: D

\sqrt{2}+1

Option D (

\sqrt{{2}}+1

) is correct because by using the triangle inequality and solving the resulting quadratic, we find the maximum value of |z|.

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