JEE MATHEMATICS MCQ: FUNCTIONS

1 Easy

1 of 1

Application +4 | -1

g\left( x \right) = 1 + \sqrt x \;and\;f\left( {g\left( x \right)} \right) = 3 + 2\sqrt x + x

then,

f\left( x \right)

is equal to

View answer and explanation

Correct option: B

2 + {x^2}

Option B is correct because by substituting g(x) into f(g(x)), we can solve for f(x) to find it equals 2 + x².

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