Question

$\smallint \,\,\sqrt {{x^2}\,\, + \,\,{a^2}} \;\,dx$ equals

Accepted Answer

$\frac{x}{2}\,\,\sqrt {{x^2} + \,\,{a^2}} \,\, + \,\,\frac{{{a^2}}}{2}\,\,\log \,\,\left\{ {x + \sqrt {{x^2} + \,\,{a^2}} } \right\}\,\, + \,\,c$

Answer

$\frac{x}{2}\sqrt {{x^2} + \,\,{a^2}} \,\, - \,\,\frac{{{a^2}}}{2}\,\,\log \,\,\left\{ {x + \sqrt {{x^2} + \,\,{a^2}} } \right\}\,\, + \,\,c$

Answer

$\frac{x}{2}\,\,\sqrt {{x^2} + \,\,{a^2}} \,\, - \,\,\frac{{{a^2}}}{2}\,\,\log \,\,\left\{ {x - \sqrt {{x^2} + \,\,{a^2}} } \right\}\,\, + \,\,c$

Answer

$\frac{x}{2}\,\,\sqrt {{x^2} + \,\,{a^2}} \,\, + \,\,\frac{{{a^2}}}{2}\,\,\log \,\,\left\{ {x - \sqrt {{x^2} + \,\,{a^2}} } \right\}\,\, + \,\,c$

JEE MATHEMATICS MCQ: INDEFINITE INTEGRATION

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