Question

$\smallint \,\,\frac{1}{{\left( {1 + {x^2}} \right)\,\,\sqrt {1 - {x^2}} }}\,\,dx$ is equal to

Accepted Answer

$\frac{1}{{\sqrt 2 }}\,\,{	an ^{ - 1}}\left( {\frac{{\sqrt 2 x}}{{\sqrt {1\,\, - \,\,{x^2}} }}} ight)$

Answer

$\frac{1}{2}\,\,{	an ^{ - 1}}\,\,\left( {\frac{{\sqrt 2 x}}{{\sqrt {1\,\, - \,\,{x^2}} }}} ight)$

Answer

$\frac{1}{{\sqrt 2 }}\,\,{	an ^{ - 1}}\,\,\left( {\frac{{\sqrt 2 x}}{{\sqrt {1\,\, + \,\,{x^2}} }}} ight)$

Answer

None of these

JEE MATHEMATICS MCQ: INDEFINITE INTEGRATION

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