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JEE MATHEMATICS MCQ: INDEFINITE INTEGRATION

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Application +4 | -1
∫dx(x−3)2x2−6x+4\int \frac{d x}{(x-3)^2 \sqrt{x^2-6 x+4}} is equal to
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Correct option: A
x2−6x+45∣x−3∣+c\frac{\sqrt{x^2-6 x+4}}{5|x-3|}+c
Option A (x2−6x+45∣x−3∣+c\frac{\sqrt{x^2-6 x+4}}{5|x-3|}+c) is correct because the integral, after substitution and simplification, results in this expression.

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