NEET UG CHEMISTRY MCQ: HYDROGEN

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Analyzing +4 | -1

An inorganic compound liberates

{\mathrm{O}_2}

when heated, turns an acid solution of KI brown and reduces acidified

\mathrm{KMn}{\mathrm{O}_4}

. The substance is:

View answer and explanation

Correct option: A

{\mathrm{H}_2}{\mathrm{O}_2}

Option B (

\mathrm{Cs}

) is correct because Cesium (Cs) is the most electropositive element among the given options due to its low ionization energy.

More Questions from HYDROGEN

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\mathrm{CaC}_2+\mathrm{H}_2 \mathrm{O} \longrightarrow \mathrm{Ca}(\mathrm{OH})_2+' \mathrm{X}\,'

\mathrm{Mg}_2 \mathrm{C}_3+\mathrm{H}_2 \mathrm{O} \longrightarrow \mathrm{Mg}(\mathrm{OH})_2+'\mathrm{Y}\,'

\mathrm{X}

\mathrm{Y}

{H_2}{O_2} \to 2{H^ + } + {O_2} + 2{e^ - };{E^0} = - 0.68V

{\mathrm{H}_\mathrm{2}}{\mathrm{O}_\mathrm{2}}

{\mathrm{H}_2}{\mathrm{O}_2}

{SiH}_4

AlH_3

{NH}_3