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JEE PHYSICS MCQ: OSCILLATIONS

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Analyzing +4 | -1
A particle, with restoring force proportional to displacement and resisting force proportional to velocity is subjected to a force. F=F0sin⁡ωtF = {F_0}\sin \omega t If the amplitude of the particle is maximum for ω=ω1{\omega _1} and the energy of the particle is maximum for ω=ω2{\omega _2} then
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Correct option: C
ω1≠ω0  and  ω2=ω0{\omega _1} \ne {\omega _0}\,\,\mathrm{and}\,\,{\omega _2} = {\omega _0}
Option C (ω1≠ω0  and  ω2=ω0{\omega _1} \ne {\omega _0}\,\,\mathrm{and}\,\,{\omega _2} = {\omega _0}) is correct because amplitude resonance occurs at a frequency slightly less than the natural frequency, while energy (or velocity) resonance occurs at the natural frequency.

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