JEE MATHEMATICS MCQ: COMPLEX NUMBERS

1 Easy

1 of 1

Application +4 | -1

Let

z

be a complex number such that

\left| z \right| + z = 3 + i

(where

i = \sqrt { - 1} )

. Then

\left| z \right|

is equal to

View answer and explanation

Correct option: B

\frac{5}{3}

Option B (5/3) is correct because by substituting

z = x + i

into the given equation and solving for x, we can find the magnitude of z.

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{\left| {1 - i} \right|^x} = {2^x}

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z \neq \pm 1

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\left|z_r-r\right| \leq r, \forall r=1,2,3, \ldots, n

\left|\sum\limits_{r=1}^n z_r\right|

(z+a b)^3=a^3

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\alpha, \beta

\gamma

|\alpha-\beta|

{z^2} + {\left| z \right|^2} = 0,

z \in C

2x = - 1 + \sqrt 3 i

{\left( {1 - {x^2} + x} \right)^6} - {\left( {1 - x + {x^2}} \right)^6}