JEE MATHEMATICS MCQ: COMPLEX NUMBERS

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Application +4 | -1

x_r=\cos \left(\pi / 3^r\right)

- i

\sin \left(\pi / 3^r\right)

, (where

i=\sqrt{-1}

). then value of

x_1 \cdot x_2 \cdot \ldots \infty

, is

View answer and explanation

Correct option: C

-{i}

Option C (-i) is correct because the product simplifies to -i using the properties of complex numbers and infinite geometric series.

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{\left| {1 - i} \right|^x} = {2^x}

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\left|\sum\limits_{r=1}^n z_r\right|

(z+a b)^3=a^3

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\alpha, \beta

\gamma

|\alpha-\beta|

{z^2} + {\left| z \right|^2} = 0,

z \in C

2x = - 1 + \sqrt 3 i

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