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JEE MATHEMATICS MCQ: FUNCTIONS

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Analyzing +4 | -1
f(x)=sin⁡2x+sin⁡2(x+π3)+cos⁡xcos⁡f(x)=\sin ^2 x+\sin ^2\left(x+\frac{\pi}{3}\right)+\cos x \cos (x+π3)\left(x+\frac{\pi}{3}\right) and g(54)=1g\left(\frac{5}{4}\right)=1, then (g∘f)(x)(g \circ f)(x) is equal to:
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Correct option: A
1
Option A (1) is correct because after simplifying f(x), it becomes a constant value of 5/4, and g(5/4) is given as 1, thus (g o f)(x) = 1.

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