JEE MATHEMATICS MCQ: 2D GEOMETRY SYSTEM

1 Easy

1 of 1

Application +4 | -1

If the points

(k, 2-2 k),(1-k, 2 k)

and

(-k-4,6-2 k)

be collinear, then the possible values of

k

are

View answer and explanation

Correct option: A

\frac{1}{2},-1

Option A (

\frac{1}{2},-1

) is correct because these values of k make the determinant of the matrix formed by the points equal to zero, indicating collinearity.

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\alpha

(\alpha, 2 \alpha)

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P

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A

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(1, \sqrt{3}),(0,0)

(2,0)

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