JEE MATHEMATICS MCQ: SYSTEM OF CIRCLES

1 Easy

1 of 1

Analyzing +4 | -1

P

and

Q

are the points of intersection of the circles

x^2+y^2+3 x+7 y+2 p-5=0

and

x^2+y^2+2 x+2 y-p^2=0

then there is a circle passing through

P, Q

and

(1,1)

for :

View answer and explanation

Correct option: A

all except one value of

p

Option A (all except one value of

p

) is correct because the equation for

\lambda

is undefined when

p = -1

, indicating that there is no circle passing through P, Q, and (1,1) for that specific value of

p

More Questions from SYSTEM OF CIRCLES

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x = 1

{x^2} + {y^2} = 4

{x^2} + {y^2} + 8y - 4 = 0

{x^2} + {y^2} + gx + 4 = 0

x^2+y^2+3 x+2 y+1=0

x^2+y^2+3 x+4 y+2=0

{x^2} + {y^2} + 2ky + 2x + 6 = 0

{x^2} + {y^2} + 2ky + k = 0

k

x^2+y^2+2 a x+c y+a=0

x^2+y^2-3 a x+d y-1=0

P

Q

5 x+b y-a=0

P

Q

x + 2y - 3 = 0

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