The total number of possible structural isomers of the compound $\left[ {{\rm{C}}{{\rm{u}}^{{\rm{II}}}}{{\left( {{\rm{N}}{{\rm{H}}_3}} \right)}_4}} \right]\left[ {{\rm{P}}{{\rm{t}}^{{\rm{II}}}}{\rm{C}}{{\rm{l}}_4}} \right]$ are:

NEET UG CHEMISTRY MCQ: CO-ORDINATION COMPOUNDS

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The total number of possible structural isomers of the compound

\left[ {\mathrm{C}{\mathrm{u}^{\mathrm{II}}}{{\left( {\mathrm{N}{\mathrm{H}_3}} \right)}_4}} \right]\left[ {\mathrm{P}{\mathrm{t}^{\mathrm{II}}}\mathrm{C}{\mathrm{l}_4}} \right]

are:

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Correct option: C

Option C (4) is correct because there are four possible linkage isomers for the given coordination compound.

Practice All Chapter MCQs →

\left[ {\mathrm{PtC}{\mathrm{l}_2}{{\left( {\mathrm{N}{\mathrm{H}_3}} \right)}_4}} \right]\mathrm{B}{\mathrm{r}_2}\mathrm{\;and\;}\left[ {\mathrm{PtB}{\mathrm{r}_2}{{\left( {\mathrm{N}{\mathrm{H}_3}} \right)}_4}} \right]\mathrm{C}{\mathrm{l}_2}\mathrm{\;}

\left[\mathrm{Cr}(\mathrm{Ox})_{2} \mathrm{ClBr}\right]^{3-}

\text{ox =}

x

{\left[ {\mathrm{Ni}{{\left( {\mathrm{CN}} \right)}_4}} \right]^x}

\mathrm{M}{\mathrm{n}^{2 + }}

\mathrm{CuS}{\mathrm{O}_4}

{\mathrm{K}_2}\left[ {\mathrm{Ni}{{\left( {\mathrm{CN}} \right)}_4}} \right]