JEE MATHEMATICS MCQ: FUNCTIONS

1 Easy

1 of 1

Application +4 | -1

The domain of the function

f\left( x \right) = \frac{{{{\sin }^1}\left( {x - 3} \right)}}{{\sqrt {9 - {x^2}} }}

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Correct option: B

\left[ {2,\mathrm{ }3} \right)

Option B ([2, 3)) is correct because it satisfies both the domain of the arcsine function and the square root function.

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f:(-\infty, 2] \longrightarrow(-\infty, 4]

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f\left( x \right) = x - \left[ x \right]

{f^{ - 1}}\left( x \right)

f: R \rightarrow R

f(x)=x^4

f(x)=(x+1)^2-1(x \geq-1)

S=\left\{x: f(x)=f^{-1}(x)\right\}