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JEE MATHEMATICS MCQ: PROPERTIES OF TRIANGLES

1 Easy

1 of 1

Analyzing +4 | -1

If in a

\triangle A B C, a \tan A+b \tan B=(a+b) \tan \frac{(A+B)}{2}

, then

View answer and explanation

Correct option: C

A=B

Option C (

A=B

) is correct because the given equation simplifies to

\tan A = \tan B

, implying

A = B

.

More Questions from PROPERTIES OF TRIANGLES

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{p_1},{p_2},{p_3}

are altitudes of a

\Delta \;ABC

drawn from the vertices

A,B,C

\Delta

the area of the triangle, then

p_1^{ - 2} + p_2^{ - 2} + p_3^{ - 2}

is equal to If the sides of the triangles are

5k,\;6k,\;5k

and radius of incircle is 6, the value of

k

is equal to In a

\Delta \,ABC

a = \left( {b - c} \right)\sec \theta

\frac{{2\,\sqrt {bc} }}{{b - c}}\,\,\sin \,\,\frac{A}{2} =

\Delta \;ABC,\frac{{b + c}}{a}

\Delta = {a^2} - {\left( {b - c} \right)^2}

\Delta

\Delta \;ABC

\tan A

A

is the area and

2 s

is the sum of the sides of a triangle, then