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JEE MATHEMATICS MCQ: COMPLEX NUMBERS

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Let z(≠2)z\left( { \ne 2} \right) be a complex number such that log⁡1/2∣z−2∣>log⁡1/2∣z∣,{\log _{1/2}}\left| {z - 2} \right| > {\log _{1/2}}\left| z \right|, then
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Correct option: A
Re  (z)>1\mathrm{Re\;}\left( z \right) > 1
Option A (Re  (z)>1\mathrm{Re\;}\left( z \right) > 1) is correct because the inequality implies that the distance from z to 2 is less than the distance from z to 0, meaning z lies to the right of the perpendicular bisector of the segment joining 0 and 2.

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