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JEE MATHEMATICS MCQ: COMPLEX NUMBERS

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Application +4 | -1
If 349(x+iy)=(32+i32)1003^{49}(x+i y)=\left(\frac{3}{2}+i \frac{\sqrt{3}}{2}\right)^{100} and x=kyx=k y, then kk is
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Correct option: D
−13-\frac{1}{\sqrt{3}}
The value of k is −13-\frac{1}{\sqrt{3}} because it is found by simplifying the given complex number equation and comparing the real and imaginary parts.

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