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JEE PHYSICS MCQ: THERMODYNAMICS

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A sample of 1 mole gas at temperature T\mathrm{T} is adiabatically expanded to double its volume. If adiabatic constant for the gas is γ=32\gamma=\frac{3}{2}, then the work done by the gas in the process is:
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Correct option: A
RT⁡[2−2]\operatorname{RT}[2-\sqrt{2}]
Option A (RT⁡[2−2]\operatorname{RT}[2-\sqrt{2}]) is correct because it represents the work done by the gas during the adiabatic expansion, calculated using the given adiabatic constant and temperature change.

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