Let $f(x)=x-3$ and $ g(x)= \begin{cases}\frac{x^2-9}{x+3} & \text { if } x \neq-3 \\ k & \text { if } x=-3\end{cases} $ If $f(x)=g(x)$ for all real $x$, then the value of $k$ is

JEE MATHEMATICS MCQ: FUNCTIONS

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Application +4 | -1

Let

f(x)=x-3

and

g(x)= \begin{cases}\frac{x^2-9}{x+3} & \text { if } x \neq-3 \\ k & \text { if } x=-3\end{cases}

f(x)=g(x)

for all real

x

, then the value of

k

View answer and explanation

Correct option: C

-6

Option C (-6) is correct because for f(x) to equal g(x) for all x, g(-3) must equal f(-3), which is -6.