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JEE PHYSICS MCQ: GRAVITATION

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According to Kepler's law of planetary motion, if TT represents time period and rr is orbital radius, then for two planets these are related as
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Correct option: C
[T1T2]2=[r1r2]3\left[\frac{T_1}{T_2}\right]^2=\left[\frac{r_1}{r_2}\right]^3
Option C (T1T22=r1r23\frac{T_1}{T_2}^2=\frac{r_1}{r_2}^3) is correct because it represents Kepler's Third Law, which relates the period and orbital radius of planets.

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