JEE MATHEMATICS MCQ: TRIGONOMETRY RATIOS

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Application +4 | -1

\cos \alpha+\cos \beta=a, \sin \alpha+\sin \beta=b

and

\alpha-\beta=2 \theta

, then

\frac{\cos 3 \theta}{\cos \theta}=

View answer and explanation

Correct option: B

a^2+b^2-3

Option B (

a^2+b^2-3

) is correct because by using the given relations and trigonometric identities, the expression

\frac{\cos 3 \theta}{\cos \theta}

simplifies to

a^2+b^2-3

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