When $20\;g$ of ${\rm{CaC}}{{\rm{O}}_3}$ were put into $10\;{\rm{ }}litre$ flask and heated to $800^\circ C$, $35\% $ of ${\rm{CaC}}{{\rm{O}}_3}$ remained unreacted at equilibrium. ${K_p}$ for decomposition of ${\rm{CaC}}{{\rm{O}}_3}$ is :

NEET UG CHEMISTRY MCQ: Equilibrium

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Application +4 | -1

When

20\;g

\mathrm{CaC}{\mathrm{O}_3}

were put into

10\;\mathrm{ }litre

flask and heated to

800^\circ C

35\%

\mathrm{CaC}{\mathrm{O}_3}

remained unreacted at equilibrium.

{K_p}

for decomposition of

\mathrm{CaC}{\mathrm{O}_3}

is :

View answer and explanation

Correct option: A

1.145\mathrm{ }\;atm

Option A is correct because it calculates the Kp for the decomposition of CaCO3 using the given percentage of unreacted CaCO3 at equilibrium.

Practice All Chapter MCQs →

Mg{(HC{O_3})_2}

MgC{O_3}

Mg{(OH)_2}

MgC{O_3}

K_{\mathrm{P}}

\mathrm{CaCO}_3

4.5 \times 10^{-2}

\mathrm{C}(\mathrm{s})+\mathrm{CO}_2(\mathrm{g}) \rightleftharpoons 2 \mathrm{CO}(\mathrm{g}),

K_{\mathrm{P}}

2.0 \mathrm{~atm}.

\mathrm{CaO}

\mathrm{CaCO}_3

+

\leftrightharpoons

\mathrm{PC}{\mathrm{l}_5}\leftrightharpoons\mathrm{PC}{\mathrm{l}_3} + \mathrm{C}{\mathrm{l}_2}

{K_{\mathrm{eq}}} = 0.41

\mathrm{p}{K_a}