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JEE MATHEMATICS MCQ: INDEFINITE INTEGRATION

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Application +4 | -1
∫esin⁡θ(log⁡sin⁡θ+cosec⁡2θ)cos⁡θdθ\int e^{\sin \theta}\left(\log \sin \theta+\operatorname{cosec}^2 \theta\right) \cos \theta d \theta is equal to
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Correct option: B
esin⁡θ(log⁡sin⁡θ−cosec⁡θ)+Ce^{\sin \theta}(\log \sin \theta-\operatorname{cosec} \theta)+C
Option B (esin⁡θ(log⁡sin⁡θ−cosec⁡θ)+Ce^{\sin \theta}(\log \sin \theta-\operatorname{cosec} \theta)+C) is correct because it results from applying integration by parts to the given integral.

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