If $y = \frac{{\tan \,\,x}}{{\tan \,\,3x}}$, then

$y\,\, \in \,\,\left[ {1/3,\,\;3} \right]$

$y\,\, \in \,\,\left[ { - 3,\,\; - 1/3} \right]$

$y\,\, \notin \,\,\left[ { - 3,\,\; - 1/3} \right]$

JEE MATHEMATICS MCQ: TRIGONOMETRY RATIOS

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Analyzing +4 | -1

y = \frac{{\tan \,\,x}}{{\tan \,\,3x}}

, then

View answer and explanation

Correct option: B

y\,\, \notin \,\,\left[ {1/3,\;\,3} \right]

Option B (

y \notin [1/3, 3]

) is correct because solving for

y = \frac{{\tan x}}{{\tan 3x}}

leads to the conclusion that y cannot lie within the closed interval [1/3, 3].