Skip to main content
Back to PROPERTIES OF TRIANGLES

JEE MATHEMATICS MCQ: PROPERTIES OF TRIANGLES

1 Easy
1 of 1
Application +4 | -1
If ΔABC,ifa=3,b=4,c=5\Delta ABC,\mathrm{if}a = 3,b = 4,c = 5, then the value of sin⁡2B\sin 2B is
View answer and explanation
Correct option: C
24/2524/25
Option C (2425\frac{{24}}{{25}}) is correct because it is the result of correctly applying the double angle formula for sine, sin⁡2B=2sin⁡Bcos⁡B\sin 2B = 2 \sin B \cos B, after finding sin⁡B\sin B and cos⁡B\cos B using the given side lengths.

More Questions from PROPERTIES OF TRIANGLES

Practice All Chapter MCQs →
Type at least 2 characters or jump directly:
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.