JEE MATHEMATICS MCQ: STRAIGHT LINES

1 Easy

1 of 1

Application +4 | -1

If the system of following equations in

x \,\&\, y

\begin{aligned} & 2 x+3 y+4=0 ; 3 x+5 y+6=0 ; \\ & 2 x^2+6 x y+5 y^2+8 x+12 y+1=t \end{aligned}

consists of a solution. Then find the numeric value of

t^4

View answer and explanation

Correct option: A

2401

The correct answer is A (2401) because it is the value of

t^4

after solving the system of equations and finding t.

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x-3 y=p, a x+2 y=q

a x+y=r

\left\{ {a{t_1}{t_2},\;a\left( {{t_1} + {t_2})\} ,\{ a{t_2}{t_3},a({t_2} + {t_3}} \right)} \right\},\;\left\{ {a{t_3}{t_1},\;a\left( {{t_3} + {t_1}} \right)} \right\}

y = 2\;x + 4

6x = 3y + 5

{x^2} + {y^2} + 2xy - 8ax - 8ay - 9{a^2} = 0

(3,8)

x+3 y=7

\left( {{x^2} + 7xy + 2{y^2}} \right)\left( {y - 1} \right) = 0