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JEE MATHEMATICS MCQ: SYSTEM OF CIRCLES

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Application +4 | -1
If the circle x2+y2+4x+22y+c=0    {x^2} + {y^2} + 4x + 22y + c = 0\;\; bisects the circumference of the circle x2+y2−2x+8y−d=0{x^2} + {y^2} - 2x + 8y - d = 0, then c+dc + d is equal to
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Correct option: B
50
Option B (50) is correct because the sum c+d is found by using the fact that the common chord passes through the center of the second circle.

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